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The dictionary meaning of LIST is a number of connected items or names written or printed consecutively, typically one below the other.
In real world, lists are considered in many ways like playlist of songs, collection of your favourite videos, a list of user database and there are many more. But, if you are given a task about handling a list of users and filter out specific users under specific conditions then it becomes a tedious job to filter the list by going through each and every user. In such scenarios, programming comes into place to make your work easier.
So, now let us understand ‘What is a LIST?’ in python programming. In python, the list is a mutable, or changeable, ordered sequence of elements where each element or value that is inside of a list is called an item.
In string, how each value/element is represented as a character similarly in list, the each value/element is separated by comma where each element can be a string, variable or constants enclosed in  bracket.
Syntax of List:
['LetsUpgrade', 'Batch1', B2, B3] Nested List: ['LetsUpgrade', ['java', 'python', 'c++'], 1, 2, ['B1', 'B2'], 'Exam']
Topics to be covered in LIST are as follows:
We are going understand the above topics through Examples not by theoretical…
Each item in a list corresponds to an index number, which is an integer value, starting with the index number 0.
For the list COURSES, the index breakdown looks like this:
print(COURSES) OUTPUT: R
If we call the list COURSES with an index number of any that is greater than 4, it will be out of range as it will not be valid:
print(COURSES) Output: IndexError: list index out of range
The above one was Positive Indexing and now let’s see Negative Indexing as shown below:
For the same list COURSES, the negative index breakdown looks like this
print(COURSES[-3]) 1 2 Output Python
#Lists are Mutable:
>>> numbers = [17, 123] >>> numbers = 5 >>> print(numbers) [17, 5]
Therefore, as per above example lists are changeable i.e mutable.
#Updating and Slicing Lists:
We can use indexing to change items within the list, by setting an index number equal to a different value. This gives us greater control over lists as we are able to modify and update the items that they contain.
If we want to change the string value of the item at index 1 from 'C++' to 'SQL', we can do so like this:
COURSES = 'SQL'
Now when we print COURSES, the list will be different:
Similarly, it goes for Negative Indexing.
We can also call out a few items from the list. Let’s say we would like to just print the middle items of sea_creatures, we can do so by creating a slice. With slices, we can call multiple values by creating a range of index numbers separated by a colon [x:y]:
print(COURSES[1:4]) 1 2 Output ['SQL', 'Python', 'R']
When creating a slice, as in [1:4], the first index number is where the slice starts (inclusive), and the second index number is where the slice ends (exclusive), which is why in our example above the items at position, 1, 2, and 3 are the items that print out.
If we want to include either end of the list, we can omit one of the numbers in the list[x:y] syntax.
print(COURSES[:3]) 1 2 Output ['Java', 'SQL', 'Python']
This printed the beginning of the list, stopping right before index 3.
To include all the items at the end of a list, we would reverse the syntax:
We can also use negative index numbers when slicing lists, just like with positive index numbers:
One last parameter that we can use with slicing is called stride, which refers to how many items to move forward after the first item is retrieved from the list. So far, we have omitted the stride parameter, and Python defaults to the stride of 1, so that every item between two index numbers is retrieved.
The syntax for this construction is list[x:y:z], with z referring to stride. Let’s make a larger list, then slice it, and give the stride a value of 2:
numbers = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12] print(numbers[1:11:2]) 1 2 Output [1, 3, 5, 7, 9]
Our construction numbers[1:11:2] prints the values between index numbers inclusive of 1 and exclusive of 11, then the stride value of 2 tells the program to print out only every other item.
We can omit the first two parameters and use stride alone as a parameter with the syntax list[::z]:
print(numbers[::3]) 1 2 Output [0, 3, 6, 9, 12]
By printing out the list numbers with the stride set to 3, only every third item is printed:
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12
Slicing lists with both positive and negative index numbers and indicating stride provides us with the control to manipulate lists and receive the output we’re trying to achieve.
#Use of operators in List:
Operators are used for modifications in lists. We’ll be using the + and * operators and their compound forms += and *=.
The + operator can be used to concatenate two or more lists together:
Now, let’s look at * operator:
Compound forms '+= ‘ & ‘ *= ‘ :
for x in range(1,4): LetsUpgrade_Courses += ['AI'] print(LetsUpgrade_Courses)
prizes = ['bike'] for x in range(1,4): prizes *= 2 print(prizes) Output ['bike', 'bike'] ['bike', 'bike', 'bike', 'bike'] ['bike', 'bike', 'bike', 'bike', 'bike', 'bike', 'bike', 'bike']
#Methods used in List:
Now, your work is to GOOGLE the below functions and understand how they work in Python Programming. (Exercise)
#Built-in functions in List:
#Deleting Elements from List:
To remove the item, we’ll use the del statement then call the list variable and the index number of that item:
To remove more than one element, you can use del with a slice index:
>>> t = ['a', 'b', 'c', 'd', 'e', 'f'] >>> del t[1:5] >>> print(t) ['a', 'f']
There are several other ways to delete elements from a list. If you know the index of the element you want, you can use pop and remove:
>>> t = ['a', 'b', 'c'] >>> x = t.pop(1) >>> print(t) ['a', 'c'] >>> print(x) b
pop modifies the list and returns the element that was removed. If you don’t provide an index, it deletes and returns the last element.
If you know the element you want to remove (but not the index), you can use remove:
>>> t = ['a', 'b', 'c'] >>> t.remove('b') >>> print(t) ['a', 'c']
#Constructing a List with List Items:
LetsUpgrade_Community = [['Frontend', 'Backend'],['Sai Sir', 'Viral Sir', 'Prasad Sawant', 'Annirudha', 'Yogesh Raghupati']]
The lists within a list are called nested list.
To access an item within this list, we will have to use multiple indices:
print(LetsUpgrade_Community) print(LetsUpgrade_Community) Output Sai Sir Frontend
#List and Strings:
Assuming that by now you know the difference between String and List, let’s convert a STRING to a list of CHARACTERS as shown below –
>>> s = 'LetsUpgrade' >>> t = list(s) >>> print(t) ['L', 'e', 't', 's','U', 'p', 'g', 'r', 'a','d', 'e']
To break a string into words, we can use the split method –
>>> s = 'FREE CODING SCHOOL' >>> t = s.split() >>> print(t) ['FREE', 'CODING', 'SCHOOL'] >>> print(t) SCHOOL
Delimiter: A delimiter is a sequence of one or more characters used to specify the boundary between separate, independent regions in plain text or other data streams.
>>> s = 'spam-spam-spam' >>> delimiter = '-' >>> s.split(delimiter) ['spam', 'spam', 'spam']
JOIN: It is the inverse of split.
>>> t = ['I am', 'a', 'LetsUpgrade', 'Student'] >>> delimiter = ' ' >>> delimiter.join(t) 'I am a LetsUpgrade Student'
Usually when we are reading a file we want to do something to the lines other than just printing the whole line. Often we want to find the “interesting lines” and then parse the line to find some interesting part of the line. What if we wanted to print out the day of the week from those lines that start with “From”?
From email@example.com Sat Jan 5 09:14:16 2008
The split method is very effective when faced with this kind of problem. We can write a small program that looks for lines where the line starts with “From”, split those lines, and then print out the third word in the line:
fhand = open('mbox-short.txt') for line in fhand: line = line.rstrip() if not line.startswith('From '): continue words = line.split() print(words)
The program produces the following output:
#Objects and values:
We will use ‘is‘ operator to check given two variables ‘a’ and ‘b’ refer to the same object or not:
>>> a = 'banana' >>> b = 'banana' >>> a is b True >>> a = [1, 2, 3] >>> b = [1, 2, 3] >>> a is b False
In the first example, Python only created one string object, and both a and b refer to it.
In the second case, we would say that the two lists are equivalent as they have the same elements, but not identical, because they are not the same object. If two objects are identical, they are also equivalent, but if they are equivalent, it is not necessary to be identical.
>>> a = [1, 2, 3] >>> b = a >>> b is a True
The association of a variable with an object is called a reference. In this example, there are two references to the same object.
An object with more than one reference has more than one name, then we say that particular object is aliased and If the aliased object is mutable, changes made with one alias affect the other:
>>> b = 25 >>> print(a) [1, 25, 3]
The above method seems to be useful but it is Error-prone and therefore, it is better to avoid using this method on mutable objects like list and for immutable objects like string is not much a problem.
def delete(t): del t S = ['a', 'b', 'c'] delete (S) print (S) ['b', 'c']
In the above example, when we pass a list to a function, the function gets a reference to the list. The caller sees the change if there is any modification in the list parameter done by function as in the above delete removes the first element from the list.
>>> t1 = [1, 2] >>> t2 = t1.append(3) >>> print(t1) [1, 2, 3] >>> print(t2) None >>> t3 = t1 +  >>> print(t3) [1, 2, 3] >>> t2 is t3 False
In the above two examples, the first one is used to Modify the existing List and the second one is used to Create a new list. Thus, output of ‘ t2 is t3 ‘ is false unless we assign it as ‘ t2 = t3 ‘.
def tail(t): t = t[2:] letters = ['a', 'b', 'c', 'f','d'] rest = tail(letters) print (rest) None def tail(t): t = t[2:] return t letters = ['a', 'b', 'c', 'f','d'] rest = tail(letters) print (rest) ['c', 'f', 'd']
If we compare above two examples, the output of both the examples vary and the reason is simple, the slice operator creates a new list and the assignment makes t refer to it, but none of that has any effect on the list that was passed as an argument.
Therefore, in second case it creates and returns a new list that is generated.
Exercise : Write a function called chop that takes a list and
modifies it, removing the first and last elements, and returns None. Then write a function called middle that takes a list and returns a newlist that contains all but the first and last elements.
It is a complex topic and to understand it properly you need go through this below Article:
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Previously published at https://olinelearning13.wordpress.com/2020/05/29/python-3-list-in-detail/