At a certain point, our Haskell programs have to be compatible with other programs running on the web. This is especially useful given the growing usage of micro-services as an architecture. Regardless, it’s very common to be transferring data between applications on different stacks. You’ll need some kind of format that allows you to transfer your data and read it on both ends. There are many different ways of doing this. But much of the current eco-system of web programming depends on the JSON format. JSON stands for “JavaScript Object Notation”. It is a way of encoding data that is compatible with Javascript programs. But it is also a useful serialization system that any language can parse. In this article, we’ll explore how to use this format for our data in Haskell. JSON 101 JSON encodes data in a few different types. There are four basic types: strings, numbers, booleans, and null values. These all functions in a predictable way. Each line here is a valid JSON value. “Hello” 4.5 3 true false null JSON then offers two different ways of combining objects. The first is an array. Arrays contain multiple values, and represent them with a bracket delimited list. Unlike Haskell lists, you can put multiple types of objects in a single array. You can even put arrays in your arrays. [1, 2, 3] [“Hello”, false, 5.5] [[1,2], [3,4]] Coming from Haskell, this kind of structure seems a little sketchy. After all, the type of whatever is in your array is not clear. But you can think of multi-type arrays as tuples, rather than lists, and it makes a bit more sense. The final and most important way to make an object in JSON is through the object format. Objects are delimited by braces. They are like arrays in that they can contain any number of values. However, each value is also assigned to a string name as a key-value pair. { “Name” : “Name”, “Age” : 23, “Grades” : [“A”, “B”, “C”]} These objects are infinitely nest-able, so you can have arrays of objects of arrays and so on. Encoding a Haskell Type So that’s all nice, but how do we actually use this format to transfer our Haskell data? We’ll let’s start with a dummy example. We’ll make a Haskell data type and show a couple possible JSON interpretations of that data. First, our type and some sample values: data Person = Person { name :: String , age :: Int , occupation :: Occupation } deriving (Show) data Occupation = Occupation { title :: String , tenure :: Int , salary :: Int } deriving (Show) person1 :: Personperson1 = Person { name = “John Doe” , age = 26 , occupation = Occupation { title = “teacher” , tenure = 5 , salary = 60000 } } person2 :: Personperson2 = Person { name = “Jane Doe” , age = 25 , occupation = Occupation { title = “engineer” , tenure = 4 , salary = 90000 } } Now there are many different ways we can choose to encode these values. The most basic way might look something like this: { “name” : “John Doe”, “age” : 26, “occupation” : { “title” : “teacher”, “tenure” : 5, “salary” : 60000 }} { “name” : “Jane Doe”, “age” : 25, “occupation” : { “title” : “engineer”, “tenure” : 4, “salary” : 90000 }} Now, we might want to help our friends using dynamically typed languages. To do this, we could provide some more context around the type contained in the object. This format might look something more like this: { “type” : “person”, “contents” : { “name” : “John Doe”, “age” : 26, “occupation” = { “type” : “Occupation”, “contents” : { “title” : “teacher”, “tenure” : 5, “salary” : 60000 } } }} Either way, we ultimately have to decide on a format with whoever we’re trying to interoperate with. It’s likely though that you’ll be working with an external API that’s already set their expectations. You have to make sure you match them. Data.Aeson Now that we know what our target values are, we need a Haskell representation for them. This comes from the library (named for the father of the mythological character “Jason”). This library contains the type . It encapsulates all the basic JSON types in its constructors. (I’ve substituted a couple type synonyms for clarity): Data.Aeson Value data Value = Object (HashMap Text Value) | Array (Vector Value) | String Text | Number Scientific | Bool Bool | Null So we see all six elements represented. So when we want to represent our items, we’ll do so using these constructors. And like with many useful Haskell ideas, we’ll use typeclasses here to provide some structure. We’ll use two typeclasses: and . We’ll first go over converting our Haskell types into JSON. We have to define the function on our type, which will turn it into a . ToJSON FromJSON toJSON Value In general, we’ll want to stick our data type into an object, and this object will have a series of “Pairs”. A is the Data.Aeson representation of a key-value pair, and it consists of a and another value. Then we’ll combine these pairs together into a JSON by using the function. We’ll start with the type, since this is somewhat simpler. Pair Text Object object Occupation {-# LANGUAGE OverloadedString #-} import Data.Aeson (ToJSON(..), Value(..), object, (.=)) ... instance ToJSON Occupation where toJSON :: Occupation -> Value toJSON occupation = object [ “title” .= toJSON (title occupation) , “tenure” .= toJSON (tenure occupation) , “salary” .= toJSON (salary occupation) ] The operator creates a for us. All our fields are simple types, which already have their own instances. This means we can use on them instead of the constructors. Note also we use the overloaded strings extension (as introduced ) since we use string literals in place of objects. Once we’ve defined our instance for the type, we can call on an occupation object. This makes it easy to define an instance for the type. .= Pair ToJSON toJSON Value here Text Occupation toJSON Person instance ToJSON Person where toJSON person = object [ “name” .= toJSON (name person) , “age” .= toJSON (age person) , “occupation” .= toJSON (occupation person) ] And now we can create JSON values from our data type! In general, we’ll also want to be able to parse JSON values and turn those into our data types. We’ll use monadic notation to encapsulate the possibility of failure. If the keys we are looking for don’t show up, we want to throw an error: import Data.Aeson (ToJSON(..), Value(..), object, (.=), (.:), FromJSON(..), withObject) ... instance FromJSON Occupation where parseJSON = withObject “Occupation” $ \o -> do title_ <- o .: “title” tenure_ <- o .: “tenure” salary_ <- o .: “salary” return $ Occupation title_ tenure_ salary_ instance FromJSON Person where parseJSON = withObject “Person” $ \o -> do name_ <- o .: “name” age_ <- o .: “age” occupation_ <- o .: “occupation” return $ Person name_ age_ occupation_ A few notes here. The functions are defined through eta reduction. This is why there seems to be no parameter. The operator can grab any data type that conforms to itself. Just as we could use with simple types like and , we can also parse them right out of the box. Plus we described how to parse an , which is why we can use the operator on the occupation field. Also, the first parameter to the function is an error message we’ll get if our parsing fails. One last note is that our and instances are inverses of each other. This is definitely a good property for you to enforce within your own API definitions. parseJSON .: FromJSON toJSON String Int Occupation withObject FromJSON ToJSON Now that we have these instances, we can see the JSON bytestrings for our different objects: >> Data.Aeson.encode person1"{\"age\":26,\"name\":\"John Doe\",\"occupation\":{\"salary\":60000,\"tenure\":5,\"title\":\"teacher\"}}">> Data.Aeson.encode person2"{\"age\":25,\"name\":\"Jane Doe\",\"occupation\":{\"salary\":90000,\"tenure\":4,\"title\":\"engineer\"}}" Deriving Instances You might look at the instances we’ve derived and think that the code looks boilerplate-y. In truth, these aren’t particularly interesting instances. Keep in mind though, an external API might have some weird requirements. So it’s good to know how to create these instances by hand. Regardless, you might be wondering if it’s possible to derive these instances in the same way we can derive or . We can, but it’s a little complicated. There are actually two ways to do it, and they both involve compiler extensions. The first way looks more familiar as a deriving route. We’ll end up putting in our types. Before we do that though, we have to get them to derive the typeclass. Eq Ord deriving (ToJSON, FromJSON) Generic is a class that allows GHC to represent your types at a level of generic constructors. To use it, you first need to turn on the compiler extension for . This lets you derive the generic typeclass for your data. You then need to turn on the extension as well. Once you have done this, you can then derive the , and instances for your types. Generic DeriveGeneric DeriveAnyClass Generic ToJSON FromJSON {-# LANGUAGE DeriveGeneric #-}{-# LANGUAGE DeriveAnyClass #-} … data Person = Person { name :: String , age :: Int , occupation :: Occupation } deriving (Show, Generic, ToJSON, FromJSON) data Occupation = Occupation { title :: String , tenure :: Int , salary :: Int } deriving (Show, Generic, ToJSON, FromJSON) With these definitions in place, we’ll get the same encoding output we got with our manual instances: >> Data.Aeson.encode person1"{\"age\":26,\"name\":\"John Doe\",\"occupation\":{\"salary\":60000,\"tenure\":5,\"title\":\"teacher\"}}">> Data.Aeson.encode person2"{\"age\":25,\"name\":\"Jane Doe\",\"occupation\":{\"salary\":90000,\"tenure\":4,\"title\":\"engineer\"}}" As you can tell, this is a super cool idea and it has widespread uses all over the Haskell ecosystem. There are many useful typeclasses with a similar pattern to and . You need the instance to satisfy a library constraint. But the instance you'll write is very boilerplate-y. You can get a lot of these instances by using the Generic typeclass together with . ToJSON FromJSON DeriveAnyClass The second route involves writing Template Haskell. Template Haskell is another compiler extension allowing GHC to generate code for you. There are many libraries that have specific Template Haskell functions. These allow you to avoid a fair amount of boilerplate code that would otherwise be very tedious. is one of these libraries. Data.Aeson First you need to enable the Template Haskell extension. Then import and you can use the simple function on your type. This will give you some spiffy new and instances. Data.Aeson.TH deriveJSON ToJSON FromJSON {-# LANGUAGE TemplateHaskell #-} import Data.Aeson.TH (deriveJSON, defaultOptions) data Person = Person { name :: String , age :: Int , occupation :: Occupation } deriving (Show) data Occupation = Occupation { title :: String , tenure :: Int , salary :: Int } deriving (Show) -- The two apostrophes before a type name is template haskell syntaxderiveJSON defaultOptions ''OccupationderiveJSON defaultOptions ''Person We’ll once again get similar output: >> Data.Aeson.encode person1"{\"name\":\"John Doe\",\"age\":26,\"occupation\":{\"title\":\"teacher\",\"tenure\":5,\"salary\":60000}}">> Data.Aeson.encode person2"{\"name\":\"Jane Doe\",\"age\":25,\"occupation\":{\"title\":\"engineer\",\"tenure\":4,\"salary\":90000}}" Unlike deriving these types wholecloth, you actually have options here. Notice we passed initially. We can change this and instead pass some modified options. For instance, we can prepend our field names with the type if we want: defaultOptions deriveJSON (defaultOptions { fieldLabelModifier = ("occupation_" ++)}) ''OccupationderiveJSON (defaultOptions { fieldLabelModifier = ("person_" ++)}) ''Person Resulting in the output: >> Data.Aeson.encode person1"{\"person_name\":\"John Doe\",\"person_age\":26,\"person_occupation\":{\"occupation_title\":\"teacher\",\"occupation_tenure\":5,\"occupation_salary\":60000}}" Template Haskell can be convenient. It reduces the amount of boilerplate code you have to write. But it will also make your code take longer to compile. There’s also a price in accessibility when you use template Haskell. Most Haskell newbies will recognize syntax. But if you use , they might be scratching their heads wondering where exactly you've defined the JSON instances. deriving deriveJSON Encoding, Decoding and Sending over Network Once we’ve defined our different instances, you might be wondering how we actually use them. The answer depends on the library you’re using. For instance, the library makes it easy. You don’t need to do any serialization work beyond defining your instances! Servant endpoints define their return types as well as their response content types. Once you've defined these, the serialization happens behind the scenes. Servant is an awesome library if you need to make an API. You should check out the at BayHac 2017 if you want a basic introduction to the library. Also take a look at the from that talk for a particular example. Servant talk I gave code samples Now, other libraries will require you to deal with JSON bytestrings. Luckily, this is also pretty easy once you’ve defined the FromJSON and ToJSON instances. As I’ve been showing in examples through the article, has the function. This will take your JSON enabled type and turn it into a that you can send over the network. Very simple. Data.Aeson encode ByteString >> Data.Aeson.encode person1"{\"name\":\"John Doe\",\"age\":26,\"occupation\":{\"title\":\"teacher\",\"tenure\":5,\"salary\":60000}}" As always, decoding is a little bit trickier. You have to account for the possibility that the data is not formatted correctly. You can call the simple function. This gives you a value, so that if parsing is unsuccessful, you’ll get . In the interpreter, you should also make sure to specify the result type you want from , or else you’ll get that it tries to parse it as , which will fail. decode Maybe Nothing decode () >> let b = Data.Aeson.encode person1>> Data.Aeson.decode b :: Maybe PersonJust (Person {name = "John Doe", age = 26, occupation = Occupation {title = "teacher", tenure = 5, salary = 60000}}) To better handle error cases though, you should prefer . This will give you a an error message if it fails. eitherDecode >> Data.Aeson.eitherDecode b :: Either String PersonRight (Person {name = "John Doe", age = 26, occupation = Occupation {title = "teacher", tenure = 5, salary = 60000}})>> let badString = "{\"name\":\"John Doe\",\"occupation\":{\"salary\":60000,\"tenure\":5,\"title\":\"teacher\"}}">> Data.Aeson.decode badString :: Maybe PersonNothing>> Data.Aeson.eitherDecode badString :: Either String PersonLeft "Error in $: key \"age\" not present" Summary So now we know all the most important points about serializing our Haskell data into JSON. The first step is to define and instances for the types you want to serialize. These are straightforward to write out most of the time. But there are also a couple different mechanisms for deriving them. Once you’ve done that, certain libraries like Servant can use these instances right out of the box. But handling manual values is also easy. You can simply use the function and the various flavors of . ToJSON FromJSON ByteString encode decode Perhaps you’ve always thought to yourself, “Haskell can’t possibly be useful for web programming.” I hope this has opened your eyes to some of the possibilities. You should try Haskell out! Download our for some pointers to some useful tools! Getting Started Checklist Maybe you’ve done some Haskell already, but you’re worried that you’re getting way ahead of yourself by trying to do web programming. You should download our . It’ll help you solidify your functional programming skills! Recursion Workbook is how hackers start their afternoons. We’re a part of the family. We are now and happy to opportunities. Hacker Noon @AMI accepting submissions discuss advertising & sponsorship To learn more, , , or simply, read our about page like/message us on Facebook tweet/DM @HackerNoon. If you enjoyed this story, we recommend reading our and . Until next time, don’t take the realities of the world for granted! latest tech stories trending tech stories
