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The Pitfalls of Implicit Returnsby@nfrankel

The Pitfalls of Implicit Returns

by Nicolas FränkelMarch 21st, 2024
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Implicit returns are a feature in some languages. They have recently bitten me, so here's my opinion.
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Implicit returns are a feature in some languages. They have recently bitten me, so here's my opinion.

Statements, expressions, and returns

Before diving into implicit returns, we must explain two programming concepts influencing them. A lot of literature is available on the subject, so I'll paraphrase one of the existing definitions:


An expression usually refers to a piece of code that can be evaluated to a value. In most programming languages, there are typically three different types of expressions: arithmetic, character, and logical.

A statement refers to a piece of code that executes a specific instruction or tells the computer to complete a task.


-- Expression vs. Statement


Here's a Kotlin snippet:


val y = 10                //1
val x = 2                 //1

x + y                     //2

println(x)                //1
  1. Statement, executes the assignment "task"
  2. Expression, evaluates to a value, e.g., 12


Functions may or may not return a value. When they do, they use the return keyword in most programming languages. It's a statement that needs an expression.


In Kotlin, it translates to the following:


fun hello(who: String): String {
    return "Hello $who"
}


In this regard, Kotlin is similar to other programming languages with C-like syntax.

Implicit returns

A couple of programming languages add the idea of implicit returns: Kotlin, Rust, Scala, and Ruby are the ones I know about; each has different quirks.


I'm most familiar with Kotlin: you can omit the return keyword when you switch the syntax from a block body to an expression body. With the latter, you can rewrite the above code as the following:


fun hello(who: String): String = "Hello $who"


Rust also allows implicit returns with a slightly different syntax.


fn hello(who: &str) -> String {
    return "Hello ".to_owned() + who;          //1
}

fn hello_implicit(who: &str) -> String {
    "Hello ".to_owned() + who                  //2
}
  1. Explicit return
  2. Transform the statement in expression by removing the trailing semicolon - implicit return


Let's continue with Kotlin. The expression doesn't need to be a one-liner. You can use more complex expressions:


fun hello(who: String?): String =
    if (who == null) "Hello world"
	else "Hello $who"

The pitfall

I was writing code lately, and I produced something akin to this snippet:


enum class Constant {
    Foo, Bar, Baz
}


fun oops(constant: Constant): String = when (constant) {
    Constant.Foo -> "Foo"
    else -> {
        if (constant == Constant.Bar) "Bar"
        "Baz"
    }
}


Can you spot the bug?

Let's use the function to make it clear:


fun main() {
	println(oops(Constant.Foo))
	println(oops(Constant.Bar))
	println(oops(Constant.Baz))
}


The results are:


Foo
Baz
Baz


The explanation is relatively straightforward. if (constant == Constant.Bar) "Bar" does nothing. The following line evaluates to "Bar"; it implicitly returns the expression. To fix the bug, we need to add an else to transform the block into an expression:


if (constant == Constant.Bar) "Bar"
else "Baz"


Note that for simpler expressions, the compiler is smart enough to abort with an error:


fun oops(constant: Constant): String =
    if (constant == Constant.Bar) "Bar"      //1
    "Baz"
  1. 'if' must have both main and 'else' branches if used as an expression

Conclusion

Implicit return is a powerful syntactic sugar that allows for more concise code. However, concise code doesn't necessarily imply being better code. I firmly believe that explicit code is more maintainable in most situations.


In this case, I was tricked by my code!

Beware of implicit returns.


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Originally published at A Java Geek on March 17th, 2024