How not to sort an array in JavaScript Array sorting is one of those things you don’t spend too long thinking about, until it stops working for you. Recently I was working with array of items in JavaScript that were not sorting at all properly and completely messing up an interface. It took me way too long to work out what went wrong so I wanted to share what happened and why it was so weird. Basic sorting JavaScript has a method available on Array objects and running it will probably do what you expect. For example: sort stringArray = [ , , , ];
stringArray.sort(); const 'cat' 'dog' 'ant' 'butterfly' // => [ 'ant', 'butterfly', 'cat', 'dog' ] It’s even pretty good if you’re sorting arrays that might have members that are . undefined MDN says that “all undefined elements are sorted to the end of the array.” stringArrayWithUndefined = [ , , , , , , ];
stringArrayWithUndefined.sort(); const 'cat' undefined 'dog' undefined 'ant' 'butterfly' 'zebra' // => [ 'ant', 'butterfly', 'cat', 'dog', 'zebra', undefined, undefined ] Gotchas The first issue you might come across is if you find yourself with an array containing . null stringArrayWithUndefinedAndNull = [ , , , , , , , ];
stringArrayWithUndefinedAndNull.sort(); const 'cat' undefined 'dog' undefined 'ant' null 'butterfly' 'zebra' // => [ 'ant', 'butterfly', 'cat', 'dog', null, 'zebra', undefined, undefined ] Sorting will coerce the to the string "null" which will appear somewhere in the middle of the alphabet. null Then there are numbers. The default JavaScript sorting algorithm is to convert all members of an array to strings and then compare their sequences of UTF-16 code unit values. This works great for arrays of strings as we’ve already seen, but it breaks down very quickly for numbers. numberArray = [ , , , ];
numberArray.sort(); biggerNumberArray = [ , , , , ];
biggerNumberArray.sort(); const 5 3 7 1 // => [ 1, 3, 5, 7 ] const 5 3 10 7 1 // => [ 1, 10, 3, 5, 7 ] In the example above, 10 gets sorted to before 3 because “10” is sorted before “3”. We can fix this by providing JavaScript a comparison function to use to perform the sort. The function receives two items from the array and it needs to return a numeric value and whether that value is above, below or equal to zero defines how the items are sorted relative to each other. If the return value is less than zero, then the first item is sorted in front of the second, if the value is above zero then the second item is sorted in front of the first. If the return value is 0 then the items stay in the same order with respect to each other. To sort numbers in ascending order, the comparison function is relatively simple: compareNumbers = a - b; const ( ) => a, b Subtracting the first item from the second one satisfies the requirements above. Using this comparison function with our from earlier will sort the numbers correctly. biggerNumberArray biggerNumberArray.sort(compareNumbers); // => [ 1, 3, 5, 7, 10 ] This still works if you have elements as they are ignored and sorted to the end. undefined numberArrayWithUndefined = [ , , , , , ];
numberArrayWithUndefined.sort(compareNumbers); const 5 undefined 3 10 7 1 // => [ 1, 3, 5, 7, 10, undefined ] causes problems again though. null numberArrayWithUndefinedAndNull = [ , , , , , , ];
numberArrayWithUndefinedAndNull.sort(compareNumbers); const 5 undefined 3 null 10 7 1 // => [ null, 1, 3, 5, 7, 10, undefined ] This happens because coercing to a number returns 0. null ( ); Number null // => 0 You could handle this in your function or be happy that it is consistent. compareNumbers Inconsistent gotchas The biggest problem, and this caught me out recently, comes when sneaks in another way. As we’ve seen, if the array contains it’s ignored and just sorted to the back. However, if you are sorting objects where the keys may be this automatic sorting doesn’t happen and the results become inconsistent. undefined undefined undefined For example, if you have an array of objects where some of them have values and some don’t, trying to sort by that value will not give you the result you want. objectArray = [
  { : },
  { : },
  {},
  { : },
  { : },
  { : }
]; compareObjects = a.value - b.value;
objectArray.sort(compareObjects); const value 1 value 10 value 5 value 7 value 3 const ( ) => a, b // => [ { value: 1 }, //      { value: 10 }, //      {}, //      { value: 3 }, //      { value: 5 }, //      { value: 7 } ] Subtracting a number from or subtracting from a number both return and since that doesn’t lay on the scale of numbers that needs from the comparison function the results end up a little strange. In this case, the item that caused the problem stays where it started in the array and the other objects are locally sorted. undefined undefined NaN sort There are a few ways around this, but the important thing is knowing that it can happen. In my case when I came across this, I filtered out the items that didn’t have a value as they weren’t important until they did. objectArray
  .filter( obj.value !== )
  .sort(compareObjects); => obj typeof 'undefined' // => [ { value: 1 }, //      { value: 3 }, //      { value: 5 }, //      { value: 7 }, //      { value: 10 } ] Beware sorting The upshot of all of this is that the sort function is not as straightforward as it might seem. Strings work, numbers need some input and while undefined is handled as a primitive you have to keep an eye on coercing s or object values. null undefined Have you come across problems sorting in JavaScript or other languages? I’d love to hear your stories too, so give me a shout on . Twitter at @philnash

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