paint-brush
Filtering Dictionary In Python 3by@melvinkcx2
5,096 reads
5,096 reads

Filtering Dictionary In Python 3

by Melvin KohJanuary 23rd, 2019
Read on Terminal Reader
Read this story w/o Javascript
tldt arrow

Too Long; Didn't Read

Python slaps you in your face when you try to add/remove entries in a dictionary during iteration during iteration. In this post, I will walk us through how we can filter a dict for a dictionary in Python. I decided to use a copy of dictionary keys to mitigate the problem when attempting to delete entries during iteration. Let’s make use of our FilterableDict, a reusable class to support filtering. In the subsequent part of this post I will use the former to illustrate how we could make our filter logic reusable.

Company Mentioned

Mention Thumbnail
featured image - Filtering Dictionary In Python 3
Melvin Koh HackerNoon profile picture

Originally published on melvinkoh.me

“RuntimeError: Dictionary changed size during iteration”, Python slaps you in your face when you try to add/remove entries in

dict
object during iteration.

In this post, I will walk us through how we can filter a

dict
collection. First, let us try to understand the problem by running this snippet in your interpreter:

from typing import Dict

def get_menu() -> Dict[str, dict]:
    return {
        "TIMMY_BLACK": {
            "item": "Timmy's Coffee Barista's Black",
            "sugar_free": True,
            "with_milk": False,
        },
        "TIMMY_LATTE": {
            "item": "Timmy's Coffee Latte",
            "sugar_free": True,
            "with_milk": False,
        },
        "TIMMY_SWEETENED_LATTE": {
            "item": "Timmy's Coffee Latte - Sweetened",
            "sugar_free": True,
            "with_milk": True,
        },
        "TIMMY_SIGNATURE_CARAMEL": {
            "item": "Timmy's Signature - Caramel Latte",
            "sugar_free": None,  # Unknown
            "with_milk": True,
        }
    }

coffees = get_menu()

# Filter unsweetened coffees -> RuntimeError
for code, details in coffees.items():
    if details.get("sugar_free") is True: 
del coffees[code]

> Try to run this snippet! ☝️

You will get a RuntimeError, as expected.

> “RuntimeError: dictionary changed size during iteration”, Python interpreter

The error message is self-explanatory and this makes perfect sense, you shouldn’t be able to expand/shrink the collection while you are looping through it. Imagine if you are allowed to do so, and you keep expanding the collection in your loop body:

import random

data = {
  1: 1,
  2: 2,
  3: 3
}

# This will raise an Error
for k in data:
  rand = random.randint(4, 2^31)
data[rand] = rand

If the above snippet is valid in Python, we will slump into infinite loop until memory is run out.

So, in any event we want to filter a

dict
object in Python, can we circumvent away from the RuntimeError? Of course!

Possible Solutions

Solution #1: Use A Shallow Copy

This is the least favorable solution, given that we have to create a new copy of the dictionary.

"""
Solution #1: Create a shallow copy of dict
"""
coffees = get_menu()  # I use this function to generate my dict object

coffee_copy = {**coffees}   # Create a shallow copy
for code, details in coffee_copy.items():
    if details.get("sugar_free") is True:
del coffees[code]

The above code will work, but it’s less hygienic to me.


Solution #2: Use A Copy Of Dictionary Keys

Another solution is instead, create a copy of dictionary keys as our iterator:

"""
Solution #2: Create a copy of keys
"""
coffees = get_menu()

key_copy = tuple(coffees.keys())    # Feel free to use any iterable collection
for k in key_copy:
    if coffees[k].get("sugar_free") is True:
del coffees[k]


Solution #3: Deferred Update

If you are against of create any copy of either the source dictionary
or the keys, we can also use the “deferred update” strategy. Deferred
update, as the name tells, is to defer any mutation to the dictionary
until the iteration is over.

"""
Solution #3: Deferred Update
Risk: What if an Exception is raised half way?
"""
coffees = get_menu()

keys_to_be_removed = []
for code, details in coffees.items():
    if details.get("sugar_free") is True:
        keys_to_be_removed.append(code)

for k in keys_to_be_removed:
del coffees[k]

However, a caveat here. Imagine an uncaught exception in between line
9 and 10, the iteration will break, all pending updates will be void
and your

dict
object will be left intact.

I personally in favor of using copy of dictionary keys and deferred
update. In the subsequent part of this post, I will use the former to
illustrate how we can make our filter logic reusable.

Making The Logic Reusable

At this point, I decided to use a copy of dictionary keys to mitigate the problem when attempting to delete entries during iteration. Let’s see how we can make the logic reusable.

In my case, I created

FilterableDict 
— a subclass of the built-in
dict
class to add
filter()
method:

class FilterableDict(dict):
    def __init__(self, *args, **kwargs):
        dict.__init__(self, *args, **kwargs)

    def filter(self, predicate):
        key_copy = tuple(self.keys())   # use Tuple to further reduce memory footprint
        for k in key_copy:
            if predicate(k, self.get(k)):
                del self[k]
        return self

    def __repr__(self):
return "FilterableDict({})".format(super().__repr__())

> FilterableDict, subclass of built-in dict class

To further reduce the memory footprint of our key copy, I use a

tuple
instead of a
list
collection to store them.

Let’s make use of our

FilterableDict
and observe the output:

> Using our FilterableDict

Here we go, a reusable class to support filtering for a dictionary in Python.

Full Source Code:

from typing import Dict

# Helper function to generate dict object
def get_menu() -> Dict[str, dict]:
    return {
        "TIMMY_BLACK": {
            "item": "Timmy's Coffee Barista's Black",
            "sugar_free": True,
            "with_milk": False,
        },
        "TIMMY_LATTE": {
            "item": "Timmy's Coffee Latte",
            "sugar_free": True,
            "with_milk": False,
        },
        "TIMMY_SWEETENED_LATTE": {
            "item": "Timmy's Coffee Latte - Sweetened",
            "sugar_free": True,
            "with_milk": True,
        },
        "TIMMY_SIGNATURE_CARAMEL": {
            "item": "Timmy's Signature - Caramel Latte",
            "sugar_free": None,  # Unknown
            "with_milk": True,
        }
    }

# Our dict subclass
class FilterableDict(dict):
    def __init__(self, *args, **kwargs):
        dict.__init__(self, *args, **kwargs)
    def filter(self, predicate):
        key_copy = tuple(self.keys())
        for k in key_copy:
            if predicate(k, self.get(k)):
                del self[k]
        return self
    def __repr__(self):
        return "FilterableDict({})".format(super().__repr__())


coffees = FilterableDict(get_menu())

coffees   # FilterableDict({...})

len(coffees)    # 4

sugar_free_filter = lambda _, v: not v["sugar_free"]

coffees.filter(sugar_free_filter)

len(coffees) # 3

Final Words

A different way to achieve the same purpose? Leave me a comment :)